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I need help with a Math problem..

starguard

Unluckiest Charm in the Box
Can anyone here help me? :)
quantum_chromodyn.jpg
 
The equations of motion in Lagrangian mechanics are Lagrange's equations, also known as Euler-Lagrange eqations Below, we sketch out the derivation of Lagrange's equation from Newtons laws of motion. See the references for more detailed and more general derivations.

Consider a single particle with mass m and position vector r. The applied force, F, can be expressed as the gradient of a scalar potential energy function V(r, t):

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Such a force is independent of third- or higher-order derivatives of r, so Newtons second law forms a set of 3 second-order ordinary differential entities. Therefore, the motion of the particle can be completely described by 6 independent variables, or degrees of freedom. An obvious set of variables is { rj, rj | j = 1, 2, 3}, the Cartesian components of r and their time derivatives, at a given instant of time (ie. position (x,y,z) and velocity (vx,vy,vz ) ).

More generally, we can work with a set of generalized coordinates, qj, and their time derivatives, the generalized velocities, qj. The position vector, r, is related to the generalized coordinates by some transformation equation:

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For example, for a simple pendulum of length l, a logical choice for a generalized coordinate is the angle of the pendulum from vertical, θ, for which the transformation equation would be

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.
The term "generalized coordinates" is really a leftover from the period when Cartesian coordinates were the default coordinate system.

Consider an arbitrary displacement δr of the particle. The work done by the applied force F is δW = F · δr. Using Newton's second law, we write:

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Since work is a physical scalar quantity, we should be able to rewrite this equation in terms of the generalized coordinates and velocities. On the left hand side,
 
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The right hand side is more difficult, but after some shuffling we obtain:

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where T = 1/2 m r′ 2 is the kinetic energy of the particle. Our equation for the work done becomes

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However, this must be true for any set of generalized displacements δqi, so we must have

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f
or each generalized coordinate δqi. We can further simplify this by noting that V is a function solely of r and t, and r is a function of the generalized coordinates and t. Therefore, V is independent of the generalized velocities:
 
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Inserting this into the preceding equation and substituting L = T - V, we obtain Lagrange's equations:

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There is one Lagrange equation for each generalized coordinate qi. When qi = ri (i.e. the generalized coordinates are simply the Cartesian coordinates), it is straightforward to check that Lagrange's equations reduce to Newton's second law.

The above derivation can be generalized to a system of N particles. There will be 6N generalized coordinates, related to the position coordinates by 3N transformation equations. In each of the 3N Lagrange equations, T is the total kinetic energy of the system, and V the total potential energy.
 
Just watch things move. There is your real answer. Just try not to put it into numbers, there are too many variables.
 
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